x^2+8(1x+28)=0

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Solution for x^2+8(1x+28)=0 equation:


Simplifying
x2 + 8(1x + 28) = 0

Reorder the terms:
x2 + 8(28 + 1x) = 0
x2 + (28 * 8 + 1x * 8) = 0
x2 + (224 + 8x) = 0

Reorder the terms:
224 + 8x + x2 = 0

Solving
224 + 8x + x2 = 0

Solving for variable 'x'.

Begin completing the square.

Move the constant term to the right:

Add '-224' to each side of the equation.
224 + 8x + -224 + x2 = 0 + -224

Reorder the terms:
224 + -224 + 8x + x2 = 0 + -224

Combine like terms: 224 + -224 = 0
0 + 8x + x2 = 0 + -224
8x + x2 = 0 + -224

Combine like terms: 0 + -224 = -224
8x + x2 = -224

The x term is 8x.  Take half its coefficient (4).
Square it (16) and add it to both sides.

Add '16' to each side of the equation.
8x + 16 + x2 = -224 + 16

Reorder the terms:
16 + 8x + x2 = -224 + 16

Combine like terms: -224 + 16 = -208
16 + 8x + x2 = -208

Factor a perfect square on the left side:
(x + 4)(x + 4) = -208

Can't calculate square root of the right side.

The solution to this equation could not be determined.

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